Jump to content
Our response time is longer than usual currently. We're working to answer users as quickly as possible and thank you for your continued patience.

Recommended Posts

its is not fully clear what you want to calculate:

  • Angle bisector
  • line bisector
  • area bisector

https://www.mathopenref.com/bisector.html

Assuming you want the first:

Only indirectly.

  1. Activate snapping.
  2. add a line (pen tool), and use snapping to match first line of triangle
  3. duplicate.
  4. use node tool to match one node to second line
  5. use transform tool to read out rotation angles of both,  and calculate difference.
  6. set decimal digits to a large number (e.g. 6) for higher accuracy.

there a numerous other possible ways. 

  1. duplicate triangle. Set opacity to 50%
  2. activate move tool.
  3. set point of origin to intersection of lines who build angle
  4. rotate duplicate until both lines of angle overlap
  5. use transform panel to read out rotation.

Or create vector shape like pie tool, position accordingly and adjust angle until it matches 

ps 

the most simple way is probably to

  1. use the rectangular shape,
  2. rotate the the head over the angle origin
  3. Roughly set angle
  4. adjust nodes until they math both lines
  5. use middle of base line (snapping) as starting point of dotted line

Mac mini M1 A2348

LG34WK950U-W, calibrated to DCI-P3 with LG Calibration Studio / Spider 5

iPad Air Gen 5 (2022) A2589

Special interest into procedural texture filter, edit alpha channel, RGB/16 and RGB/32 color formats, stacking, finding root causes for misbehaving files, finding creative solutions for unsolvable tasks, finding bugs in Apps.

 

Link to comment
Share on other sites

6 hours ago, NotMyFault said:

its is not fully clear what you want to calculate:

  • Angle bisector
  • line bisector
  • area bisector

 

Too early here on the wet coast but.... Wouldn't line and area bisector be the same result? Two triangles with base of 4 units and height of 2 units will both be 4 square units in area. If I bisect base so I have base of 2 and (the same) height of 2 then the areas will be 2 square units. (B * H)/2 gives you the area of a triangle.

Mac Pro (Late 2013) Mac OS 11.7.3 
Affinity Designer 2.0.4 | Affinity Photo 2.0.4 | Affinity Publisher 2.0.4 | Beta versions as they appear.

I have never mastered color management, period, so I cannot help with that.

Link to comment
Share on other sites

1 hour ago, Old Bruce said:

Wouldn't line and area bisector be the same result?

Only in special cases like yours, not in general.

use the example from OP, both will be totally different. 

Mac mini M1 A2348

LG34WK950U-W, calibrated to DCI-P3 with LG Calibration Studio / Spider 5

iPad Air Gen 5 (2022) A2589

Special interest into procedural texture filter, edit alpha channel, RGB/16 and RGB/32 color formats, stacking, finding root causes for misbehaving files, finding creative solutions for unsolvable tasks, finding bugs in Apps.

 

Link to comment
Share on other sites

This is what I was thinking of. Obviously the angles abd and dbc are not equal, they are not bisected. The areas of abd and dbc are equal as are the line lengths ad and dc. Two examples given.

2024967796_ScreenShot2022-07-09at9_25_59AM.png.68ccbdc8c4bb0c5af1d624a9e1ddf8c1.png

Mac Pro (Late 2013) Mac OS 11.7.3 
Affinity Designer 2.0.4 | Affinity Photo 2.0.4 | Affinity Publisher 2.0.4 | Beta versions as they appear.

I have never mastered color management, period, so I cannot help with that.

Link to comment
Share on other sites

8 hours ago, NotMyFault said:

its is not fully clear what you want to calculate:

  • Angle bisector
  • line bisector
  • area bisector

https://www.mathopenref.com/bisector.html

Assuming you want the first:

Only indirectly.

  1. Activate snapping.
  2. add a line (pen tool), and use snapping to match first line of triangle
  3. duplicate.
  4. use node tool to match one node to second line
  5. use transform tool to read out rotation angles of both,  and calculate difference.
  6. set decimal digits to a large number (e.g. 6) for higher accuracy.

there a numerous other possible ways. 

  1. duplicate triangle. Set opacity to 50%
  2. activate move tool.
  3. set point of origin to intersection of lines who build angle
  4. rotate duplicate until both lines of angle overlap
  5. use transform panel to read out rotation.

Or create vector shape like pie tool, position accordingly and adjust angle until it matches 

ps 

the most simple way is probably to

  1. use the rectangular shape,
  2. rotate the the head over the angle origin
  3. Roughly set angle
  4. adjust nodes until they math both lines
  5. use middle of base line (snapping) as starting point of dotted line

thanks i will try later

Link to comment
Share on other sites

2 hours ago, Old Bruce said:

Too early here on the wet coast but.... Wouldn't line and area bisector be the same result? Two triangles with base of 4 units and height of 2 units will both be 4 square units in area. If I bisect base so I have base of 2 and (the same) height of 2 then the areas will be 2 square units. (B * H)/2 gives you the area of a triangle.

i not so clear on my question. hi From Chile here. I need a tool to angle bisector, in one corner of the triangle to construct a dot line.

Link to comment
Share on other sites

28 minutes ago, Old Bruce said:

This is what I was thinking of. Obviously the angles abd and dbc are not equal, they are not bisected. The areas of abd and dbc are equal as are the line lengths ad and dc. Two examples given.

2024967796_ScreenShot2022-07-09at9_25_59AM.png.68ccbdc8c4bb0c5af1d624a9e1ddf8c1.png

thanks, but I need angle bisector, not area bisector. Thanks a lot.

1 hour ago, NotMyFault said:

Only in special cases like yours, not in general.

use the example from OP, both will be totally different. 

Thanks!!

Link to comment
Share on other sites

We have gone off on a different angle here. 

Yes, you cannot bisect an angle using any of the Affinity applications.

Not without some fairly serious work, think back to geometry lessons in school using a compass and a  straight edge.

Mac Pro (Late 2013) Mac OS 11.7.3 
Affinity Designer 2.0.4 | Affinity Photo 2.0.4 | Affinity Publisher 2.0.4 | Beta versions as they appear.

I have never mastered color management, period, so I cannot help with that.

Link to comment
Share on other sites

3 minutes ago, Old Bruce said:

We have gone off on a different angle here. 

I see what you did there, have a haha

Microsoft Windows 10 Home, Intel i7-9750H CPU @ 2.60GHz, 16 GB RAM, 500GB SSD, 1TB Whirlygig, NVIDIA GeForce RTX 2060
Affinity Photo - 24/05/20, Affinity Publisher - 06/12/20, KTM Superduke - 27/09/10

Link to comment
Share on other sites

14 minutes ago, David in Яuislip said:

Good man, I was hoping you'd be watching

I was indeed watching, so I’d only have missed it if I were somewhat obtuse.

Alfred spacer.png
Affinity Designer/Photo/Publisher for Windows 1.10 • Windows 10 Home/Pro
Affinity Photo for iPad 1.10 • Designer for iPad 1.10 • iPadOS 15.6.1 (iPad Air 2)

Link to comment
Share on other sites

40 minutes ago, Alfred said:

I was indeed watching, so I’d only have missed it if I were somewhat obtuse.

Hmmm, there is no built in [appreciative groan emoticon] emoji in the forum software.

Obtuse. You? Never! Me on the other hand...

Mac Pro (Late 2013) Mac OS 11.7.3 
Affinity Designer 2.0.4 | Affinity Photo 2.0.4 | Affinity Publisher 2.0.4 | Beta versions as they appear.

I have never mastered color management, period, so I cannot help with that.

Link to comment
Share on other sites

Another creative solution:

  1. move angle origin in the center of quadratic canvas
  2. align one line to horizontal right
  3. add fill layer behind
  4. merge visible
  5. use equations
  6. set to polar
  7. set t=t*2
  8. apply
  9. set blend range to make white half transparent
  10. the result shows the bisector of the angle (in the middle of both lines building the angle)

54F87658-9F9D-4D55-ADD7-5F0F3271FD3D.png

Mac mini M1 A2348

LG34WK950U-W, calibrated to DCI-P3 with LG Calibration Studio / Spider 5

iPad Air Gen 5 (2022) A2589

Special interest into procedural texture filter, edit alpha channel, RGB/16 and RGB/32 color formats, stacking, finding root causes for misbehaving files, finding creative solutions for unsolvable tasks, finding bugs in Apps.

 

Link to comment
Share on other sites

17 hours ago, CreacionesOrigami said:

Hello People!!, I´m just starting in Affinity Designer. I hope you can help me.

Is there a tool to calculate the bisector of an angle in a triangle?

Thanks!!

image.png.d766d7a2448b372d1cd52266714a31d5.png

OK. I think this will explain better what i want to get, without to make every time the circles.

I'm looking for a tool to construct the dot line over the angle bisector of a triangle corner. 

image.png.c36e31f60202d8240cee099321fa9ffe.png

Link to comment
Share on other sites

4 minutes ago, CreacionesOrigami said:

OK. I think this will explain better what i want to get, without to make every time the circles.

I'm looking for a tool to construct the dot line over the angle bisector of a triangle corner. 

To paraphrase GarryP from his first post. I don't think there is an easy or automatic way of doing this in any of the Affinity applications.

Mac Pro (Late 2013) Mac OS 11.7.3 
Affinity Designer 2.0.4 | Affinity Photo 2.0.4 | Affinity Publisher 2.0.4 | Beta versions as they appear.

I have never mastered color management, period, so I cannot help with that.

Link to comment
Share on other sites

44 minutes ago, NotMyFault said:

Another creative solution:

  1. move angle origin in the center of quadratic canvas
  2. align one line to horizontal right
  3. add fill layer behind
  4. merge visible
  5. use equations
  6. set to polar
  7. set t=t*2
  8. apply
  9. set blend range to make white half transparent
  10. the result shows the bisector of the angle (in the middle of both lines building the angle)

54F87658-9F9D-4D55-ADD7-5F0F3271FD3D.png

thanks

Link to comment
Share on other sites

2 hours ago, CreacionesOrigami said:

OK. I think this will explain better what i want to get, without to make every time the circles.

I'm looking for a tool to construct the dot line over the angle bisector of a triangle corner. 

Because this silly little program has some capabilities 😜 (in this case rotating something 90º) you only need to draw one circle.

Draw a circle with the center point at the angle you want to bisect.
Connect the two crossing points with your dashed line.
Rotate the line 90º around it's center point (with move tool by toggling the bounding box.... or with the node tool transform mode.... or with point transform tool)

It's not automagic (like it probably should be), but since you need to draw the dashed line anyway it's really just one more shape. Not terrible (if you don't have to do a lot.... 🥴).

Edit: Sorry, didn't leave anything punny. Just my attempt to unt-angle this thread. 😶

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
 Share

×
×
  • Create New...

Important Information

Please note there is currently a delay in replying to some post. See pinned thread in the Questions forum. These are the Terms of Use you will be asked to agree to if you join the forum. | Privacy Policy | Guidelines | We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.