Aff.Des.1.10.5: Power duplicate circles

[catlover]

Please see example attachment:

I have to duplicate the small circles along the entire path formed by the middle circle.

Turn on "enable transform origin" to see the common midpoint of the circles.

Can't figure out how to do this by power duplicating.

Any help is vastly appreciated, thanks !

C.L.

circles.afdesign

[GarryP]

1. Find the circumference of the middle circle (C=pi*diameter) [diameter is the circle width in this case].
2. Divide that number by the diameter of the small circle (D=C/smalld).
3. Then divide 360 by that number (R = 360/D).

• Select the small circle.
• Enable Transform Origin.
• Move the Transform Origin to the centre of the middle circle.
• Duplicate the layer.
• Enter the R value you calculated earlier into the R field of the Transform Panel.
• Duplicate, Duplicate, etc. etc.

You might need to tweak the rotation value if it doesn’t come out quite right because of rounding errors.

[v_kyr]

Or alternatively try out text on path, but instead of inserting artistic text there (on one selected bigger lead/guide circles) paste in your little circle repeatedly.

[v_kyr]

Or probably the most flexible, let Python instead do the work of distributing smaller circles around a bigger circle (where you can define the radi for the big and small circles and the number of small circles) and then save the whole as in ADe reusable SVG code. - A little Python script ...

import numpy as np
import matplotlib.pyplot as plt

num_circ = 7
rad_large = 7
rad_small = 4
thetas = np.linspace(0, 2 * np.pi, num_circ, endpoint=False)

fig, ax = plt.subplots()
ax.add_patch(plt.Circle((0, 0), rad_large, fc='none', ec='navy'))
for theta in thetas:
    ax.add_patch(plt.Circle((rad_large * np.cos(theta), rad_large * np.sin(theta),), rad_small, fc='none', ec='crimson'))
ax.autoscale_view() # calculate the limits for the x and y axis
ax.set_aspect('equal') # show circles as circles
plt.savefig("myimg.svg") # save as SVG
plt.show()

• myimg.svg
• myimg.afdesign
• circles.py  (the Python script)

[Old Bruce]

3 hours ago, catlover said:

I have to duplicate the small circles along the entire path formed by the middle circle.

Turn on "enable transform origin" to see the common midpoint of the circles.

Can't figure out how to do this by power duplicating.

I think what you are wanting to do is get 26 circles of 35 mm distributed.

Be aware that in this case it is possible to do so, however if you wanted a different size it may not be possible. Geometry. 

Divide the 360 degrees by 26 and that should do it. In future you'll need to remember that only some sizes of the smaller circle will fit into a pair of inner and outer circles.

[v_kyr]

2 hours ago, Old Bruce said:

I think what you are wanting to do is get 26 circles of 35 mm distributed. ...

If that is meant, that's easy to do with the above script slightly adapted too then (...here the python SVG result is placed on the OP's initial A4 portrait page).

• circles_py_v_kyr.afdesign

 

[catlover]

Thank you all very much for your help. ! 😀

C.L.