Publisher: How do you use Regular Expressions with Find and Replace?

[big smile]

This is my text

01 New Day
02 Moonlight in the dark night
03 Another Song and Dance.

I need to insert a line break after the two digits.

I enter the following:

Find: \d\d\s
Replace \d\d\n

The line break gets inserted, but my numbers get replaced with dd

e.g.

dd
New Day

dd
Moonlight in the dark night

dd
Another Song and Dance.

 

How can I get it replaced properly, so I keep my numbers, while also having the line break. Thanks!

Also, the line break seems to be a paragraph break and note a line break. 

 

 

[lacerto]

(...)

[big smile]

12 minutes ago, Lagarto said:

I suck in regex so this is probably not right, but seems to work in this specific case:

You can learn regex e.g. at . https://regex101.com/

Thank you so much. Using \n still produced a paragraph break instead of a line break, but I could use the "Special Characters" menu in the "Replace field" to add a line break. 

[lacerto]

(...)

[E9B6]

I wanted to replace paragraph, paragraph with just one paragraph

In page plus it would have been ^p^p replace with ^p

But for the life of me I cannot see how to do this in publisher.

[Old Bruce]

45 minutes ago, E9B6 said:

In page plus it would have been ^p^p replace with ^p

Publisher can use regular expressions for find and replace. You will need to use \r\r for the find term and \r  for the replace term. You turn on regular expressions by using the cog wheel on the left of the Find terms.

In the code used for regular expressions ^p means "the beginning of a line followed by a 'p' "

[carl123]

58 minutes ago, E9B6 said:

I wanted to replace paragraph, paragraph with just one paragraph

In page plus it would have been ^p^p replace with ^p

But for the life of me I cannot see how to do this in publisher.

 

Click the small down arrow in the Find input field and select Special Characters

Do the same for the Replace With input field

 

[Moshood]

Hello, to insert line break after digit

find: (\d+)\s(\w)

replace: $1\r$2